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63x^2+32x-63=0
a = 63; b = 32; c = -63;
Δ = b2-4ac
Δ = 322-4·63·(-63)
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16900}=130$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-130}{2*63}=\frac{-162}{126} =-1+2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+130}{2*63}=\frac{98}{126} =7/9 $
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